Diferencia entre revisiones de «Espectro de un operador»

Contenido eliminado Contenido añadido
mSin resumen de edición
Línea 102:
 
==Espectro de operadores no acotados==
La definición de espectro
 
 
<!--
== Spectrum of unbounded operators ==
One can extend the definition of spectrum for [[unbounded operator]]s on a [[Banach space]] ''X'', operators which are no longer elements in the Banach algebra ''B''(''X''). One proceeds in a manner similar to the bounded case. A complex number <math>\lambda</math> is said to be in the '''resolvent set''', that is, the [[complement (set theory)|complement]] of the spectrum of a linear operator
 
:<math>T: D \subset X \to X</math>
 
if the operator
 
:<math>T-\lambda I: D \to X</math>
 
has a bounded inverse, i.e. if there exists a bounded operator
 
:<math>S : X \rightarrow D</math>
 
such that
 
:<math>S (T - \lambda) = I_D, \, (T - \lambda) S = I_X.</math>
 
A complex number <math>\lambda</math> is then in the '''spectrum''' if this property fails to hold. One can classify the spectrum in exactly the same way as in the bounded case.
 
The spectrum of an unbounded operator is in general a closed, possibly empty, subset of the complex plane.
 
Immediately from the definition, it can be deduced that ''S'' can not be invertible, in the sense of bounded operators. Since the domain ''D'' may be a proper subset of ''X'', the expression
 
:<math>\, (T - \lambda) S = I_X</math>
 
makes sense only if ''Ran''(''S'') is contained in ''D''. Similarly,
 
:<math>\, S (T - \lambda) = I_D</math>
 
implies ''D'' &sub; ''Ran''(''S''). Therefore, ''λ'' being in the resolvent set of ''T'' means
 
:<math>T-\lambda I: D \to X</math>
 
is bijective. (Recall that bijectivity of ''T - &lambda;'' is not implied by invertibility if ''T'' is bounded.)
 
The converse is true if one introduces the additional assumption that ''T'' is closed. By the [[closed graph theorem]], if ''T - λ'': ''D'' &rarr; ''X'' is bijective, then its (algebraic) inverse map is necessarily a bounded operator. (Notice the completeness of ''X'' is required in invoking the closed graph theorem.) Therefore, in contrast to the bounded case, the condition that a complex number ''λ'' lie in the spectrum of ''T'' becomes a purely algebraic one: for a closed <math>T</math>, <math>\lambda</math> is in the spectrum of <math>T</math> if and only if <math>T-\lambda</math> is not bijective.
-->
==Ejemplos==
===Operador momento lineal===
Línea 151 ⟶ 191:
*Richtmyer, Robert D. (1978): ''Principles of advanced mathematical physics'', Springer-Verlag, New York, ISBN 0-387-08873-3.
 
<!--
== Spectrum of unbounded operators ==
One can extend the definition of spectrum for [[unbounded operator]]s on a [[Banach space]] ''X'', operators which are no longer elements in the Banach algebra ''B''(''X''). One proceeds in a manner similar to the bounded case. A complex number <math>\lambda</math> is said to be in the '''resolvent set''', that is, the [[complement (set theory)|complement]] of the spectrum of a linear operator
 
:<math>T: D \subset X \to X</math>
 
if the operator
 
:<math>T-\lambda I: D \to X</math>
 
has a bounded inverse, i.e. if there exists a bounded operator
 
:<math>S : X \rightarrow D</math>
 
such that
 
:<math>S (T - \lambda) = I_D, \, (T - \lambda) S = I_X.</math>
 
A complex number <math>\lambda</math> is then in the '''spectrum''' if this property fails to hold. One can classify the spectrum in exactly the same way as in the bounded case.
 
The spectrum of an unbounded operator is in general a closed, possibly empty, subset of the complex plane.
 
Immediately from the definition, it can be deduced that ''S'' can not be invertible, in the sense of bounded operators. Since the domain ''D'' may be a proper subset of ''X'', the expression
 
:<math>\, (T - \lambda) S = I_X</math>
 
makes sense only if ''Ran''(''S'') is contained in ''D''. Similarly,
 
:<math>\, S (T - \lambda) = I_D</math>
 
implies ''D'' &sub; ''Ran''(''S''). Therefore, ''λ'' being in the resolvent set of ''T'' means
 
:<math>T-\lambda I: D \to X</math>
 
is bijective. (Recall that bijectivity of ''T - &lambda;'' is not implied by invertibility if ''T'' is bounded.)
 
The converse is true if one introduces the additional assumption that ''T'' is closed. By the [[closed graph theorem]], if ''T - λ'': ''D'' &rarr; ''X'' is bijective, then its (algebraic) inverse map is necessarily a bounded operator. (Notice the completeness of ''X'' is required in invoking the closed graph theorem.) Therefore, in contrast to the bounded case, the condition that a complex number ''λ'' lie in the spectrum of ''T'' becomes a purely algebraic one: for a closed <math>T</math>, <math>\lambda</math> is in the spectrum of <math>T</math> if and only if <math>T-\lambda</math> is not bijective.
-->
==Referencias==
{{reflist}}